To convert a list to a tree in Go, you can use recursion. Here is an example implementation:
type Node struct {
Value int
Left *Node
Right *Node
}
func ListToTree(lst []int) *Node {
if len(lst) == 0 {
return nil
}
mid := len(lst) / 2
node := &Node{Value: lst[mid]}
node.Left = ListToTree(lst[:mid])
node.Right = ListToTree(lst[mid+1:])
return node
}
This function takes in a sorted list of integers and recursively constructs a binary search tree from it. The middle element of the list is chosen as the root of the current subtree, and the left and right subtrees are recursively constructed from the elements on either side of the middle element.
For example, given the list [1, 2, 3, 4, 5], this function would construct the following binary search tree:
3
/ \
1 4
\ \
2 5
![/data # iw --debug dev wlan0 connect -w "lucky-5g" auth open key 0:1234567890
Usage: iw [options] dev connect [-w] [] [] [auth open|shared] [key 0:abcde d:1:6162636465] [mfp:req/opt/no]
Join the network with ...](https://linuxcpp.0voice.com/zb_users/upload/2023/05/202305162239148267954.png)
![驱动代码
void kalRxTaskletSchedule(struct GLUE_INFO *pr)
{
static unsigned int num = 0;
tasklet_hi_schedule(&pr->rRxTask[(num++)%NR_CPUS]);
// tasklet_hi_schedule(&pr->rRxTask);
DBGLOG(HAL, ERROR,](https://linuxcpp.0voice.com/zb_users/upload/2023/05/202305162226144313964.png)
