可以将两个条件进行合并，这样在提交时可以根据不同的情况执行相应的逻辑。下面是合并后的代码示例：
handleFilterSubmit(isSave) {if (isSave || this.state.activeKey === 6) {const values = {...this.props.productData,status: 'prodPass',note: this.basicRef.formVales.note,// seq: '',fpmsBaseInfo: this.basicIfo,fpmsControlInfo: this.caculateRef.formVales,fpmsCostAccountingInfo: this.controllRef.formVales,fpmsPeriodPublicationInfo: this.periodRef.terms,fpmsFileInfo: this.fileRef.files,limitCode: this.limitCodeRef.limitCode};const { type } = this.props.params;console.log(values, type, '903420943295u238y5782352390502359');if ((type === 'add' || type === 'copy') && isSave) {this.addProductModel(values);} else {const status = type === 'wh' ? null : values.status;this.updateProduct({ ...values, status });}if (this.state.activeKey === 6) {if (values.fpmsBaseInfo && values.fpmsBaseInfo.payType) {const payTypeValues = values.fpmsBaseInfo.payType;if (!Array.isArray(payTypeValues)) {const payTypeArray = payTypeValues.split(',');values.fpmsBaseInfo.payType = payTypeArray;}}this.props.productInput(values, () => {window.location.href = '/productFactory/product/template';this.props.queryProducts();});}} else {this.setState(prevState => ({activeKey: prevState.activeKey + 1}));}}
通过合并条件，如果isSave为真或者activeKey为6时，会执行相应的提交逻辑。
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