用c++伪代码编写一个最小耗费分支限界算法寻找最小的顶点覆盖，并确定算法的复杂度。-Go服务器开发

以下是一个使用C++伪代码编写的最小耗费分支限界算法来寻找最小的顶点覆盖：

#include <iostream>
#include <vector>
#include <queue>
using namespace std;
struct Node {
    int vertex;
    int cost;
    vector<int> selectedVertices;
};
int minVertexCover(vector<vector<int>>& graph, vector<bool>& selected) {
    int n = graph.size();
    queue<Node> q;
    Node root;
    root.vertex = 0; // 从顶点0开始
    root.cost = 0;
    root.selectedVertices.resize(n, false);
    
    q.push(root);
    int minCost = INT_MAX;
    while (!q.empty()) {
        Node current = q.front();
        q.pop();
        int level = current.vertex + 1; // 下一层要处理的顶点
        if (level == n) { // 到达叶子节点，更新最小耗费值
            if (current.cost < minCost)
                minCost = current.cost;
            continue;
        }
        Node leftChild, rightChild;
        leftChild.vertex = level;
        rightChild.vertex = level;
        leftChild.cost = current.cost; // 左子树不选择当前顶点
        rightChild.cost = current.cost + 1; // 右子树选择当前顶点
        leftChild.selectedVertices.assign(current.selectedVertices.begin(), current.selectedVertices.end());
        rightChild.selectedVertices.assign(current.selectedVertices.begin(), current.selectedVertices.end());
        q.push(leftChild);
        
        if (!selected[current.vertex]) {
            rightChild.selectedVertices[current.vertex] = true;
            q.push(rightChild);
         }
    }
    return minCost;
}
int main() {
    int n; // 顶点数量
    cin >> n;
    vector<vector<int>> graph(n, vector<int>(n));
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            cin >> graph[i][j]; // 输入邻接矩阵
        }
    }
    vector<bool> selected(n, false); // 记录被选择的顶点
    int minCoverCost = minVertexCover(graph, selected);
    cout << "Minimum vertex cover cost: " << minCoverCost << endl;
    return 0;
}