根据给出的代码，可以实现如下的输出函数OutputShortestPath来输出最短路径和距离：
void OutputShortestPath(ALDirNetwork<char, int>& graph, int v, int* dist, int* path){char vertex = graph.GetValue(v);for (int i = 0; i < graph.GetVexNum(); i++) {if (i != v) {char destVertex = graph.GetValue(i);std::cout << "The shortest path between " << vertex << " and " << destVertex << " is: ";// 输出路径std::stack<int> stack;int index = i;while (path[index] != -1) {stack.push(index);index = path[index];}std::cout << vertex;while (!stack.empty()) {std::cout << " " << graph.GetValue(stack.top());stack.pop();}// 输出距离if (dist[i] == graph.GetInfinity()) {std::cout << "\nThere is no path between " << vertex << " and " << destVertex;} else {std::cout << "\nThe distance is: " << dist[i];}std::cout<<std::endl;}}}
你可以在主程序中调用该函数，传入图、起点、最短距离数组和路径数组来进行输出。注意要先调用Dijkstra算法函数获取最短距离和路径。
希望对你有所帮助！
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