以下是使用单链表的其他方法实现该代码:
#include <iostream>
#include <iomanip>
#include <string>
using namespace std;
struct LNode
{
// 存储数据
int month;
int day;
string name;
double price;
LNode* next; // 后继指针
LNode() {}
LNode(int a, int b, const string& c, double d, LNode* n = nullptr)
: month(a), day(b), name(c), price(d), next(n) {}
};
class List
{
public:
int _size;
LNode* head;
void init()
{
head = new LNode;
head->next = nullptr;
_size = 0;
}
public:
List() { init(); } // 构造函数
~List()
{
while (head)
{
LNode* p = head->next;
delete head;
head = p;
}
}; // 析构函数
// 头插法
void insert(int a, int b, const string& c, double d)
{
_size++;
LNode* p = new LNode(a, b, c, d);
p->next = head->next;
head->next = p;
};
// 在指定位置插入元素
void insert(int index, int a, int b, const string& c, double d)
{
if(index <= 0 || index > _size + 1) return;
_size++;
LNode* p = head;
for (int i = 0; i < index - 1; i++)
p = p->next;
LNode* tmp = new LNode(a, b, c, d);
tmp->next = p->next;
p->next = tmp;
};
void print_L()
{
LNode* p = head->next;
while (p)
{
cout << p->month << " " << p->day << " ";
p = p->next;
}
cout << endl;
};
int located(int a, int b)
{
LNode* p = head->next;
int e = 1;
while (p)
{
if (a < p->month)
{
e++;
p = p->next;
if (!p) return e;
}
else if (a > p->month)
{
return e;
}
else if (a == p->month)
{
if (b < p->day)
{
e++;
p = p->next;
if (!p) return e;
}
else if (b > p->day)
{
return e;
}
else if (b == p->day)
{
return e;
}
}
}
return -1; // 没有找到
};
};
int main()
{
int m, n;
string str;
string c;
double d;
List L1;
double ave1 = 0;
double ave2 = 0;
cin >> m >> n;
for (int i = 0; i < m; i++)
{
cin >> str >> c >> d;
int a = stoi(str.substr(2));
int b = stoi(str.substr(0, 2));
int e = L1.located(a, b);
L1.insert(e, a, b, c, d);
}
double sum1 = 0;
int count1 = 0;
double sum2 = 0;
int count2 = 0;
LNode* p = L1.head->next;
for (int i = 0; i < m && count1 < n; i++)
{
if (p->name == "keyboard")
{
sum1 += p->price;
count1++;
}
p = p->next;
}
LNode* s = L1.head->next;
for (int i = 0; i < m && count2 < n; i++)
{
if (s->name == "mouse")
{
sum2 += s->price;
count2++;
}
s = s->next;
}
cout << fixed << setprecision(1) << sum1 / n << endl;
cout << fixed << setprecision(1) << sum2 / n << endl;
return 0;
}
此实现使用了单链表的头插法和指定位置插入元素的方法,实现了与原始代码相同的功能。
内容由零声教学AI助手提供,问题来源于学员提问