您需要对uploadHandler函数进行修改，以便在文件和信息保存成功后返回成功的响应。以下是修改后的代码示例：
package mainimport ("fmt""io/ioutil""mime/multipart""net/http")func main() {http.HandleFunc("/upload", uploadHandler)err := http.ListenAndServe(":8888", nil)if err != nil {fmt.Println("Server error:", err)}}func uploadHandler(w http.ResponseWriter, r *http.Request) {if r.Method != "POST" {w.WriteHeader(http.StatusMethodNotAllowed)return}file, handler, err := r.FormFile("file")if err != nil {w.WriteHeader(http.StatusBadRequest)fmt.Fprint(w, "Failed to retrieve file from request.")return}defer file.Close()info := r.FormValue("info")saveFile(file, handler.Filename)saveInfo(info)response := struct {Status int `json:"status"`Message string `json:"message"`}{Status: http.StatusOK,Message: "success",}w.Header().Set("Content-Type", "application/json")w.WriteHeader(http.StatusOK)json.NewEncoder(w).Encode(response)}func saveFile(file multipart.File, filename string) {data, err := ioutil.ReadAll(file)if err != nil {fmt.Println("Failed to read file data:", err)return}// 将文件保存在当前目录下filePath := "./" + filenameerr = ioutil.WriteFile(filePath, data, 0644)if err != nil {fmt.Println("Failed to save file:", err)return}fmt.Println("File saved:", filePath)}func saveInfo(info string) {infoFilePath := "./info.txt"err := ioutil.WriteFile(infoFilePath, []byte(info), 0644)if err != nil {fmt.Println("Failed to save info:", err)return}fmt.Println("Info saved:", infoFilePath)}
以上代码在文件和信息保存成功后，将返回一个状态码为200、消息为”success”的JSON响应。
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