您可以使用MySQL的IFNULL函数来处理这种情况。将FIND_IN_SET(recv.id, stra.receivers)作为第一个参数传递给IFNULL函数，并在没有结果时返回空字符串。
修改后的代码如下：
$log_list = Db::name('notification_strategy')
->alias('stra')
->join('notification_receiver recv', 'FIND_IN_SET(recv.id, stra.receivers)', 'LEFT')
->whereIn('stra.department_id', $curdepartment_childrens)
->where($where)
->field('stra.*, IFNULL(GROUP_CONCAT(recv.nickname), "") as receivers')
->order('stra.create_time desc')
->group('stra.id')
->paginate($data['limit']);
这样，如果没有匹配的receivers，则会显示空字符串。
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![/data # iw --debug dev wlan0 connect -w "lucky-5g" auth open key 0:1234567890
Usage: iw [options] dev connect [-w] [] [] [auth open|shared] [key 0:abcde d:1:6162636465] [mfp:req/opt/no]
Join the network with ...](https://linuxcpp.0voice.com/zb_users/upload/2023/05/202305162239148267954.png)
![驱动代码
void kalRxTaskletSchedule(struct GLUE_INFO *pr)
{
static unsigned int num = 0;
tasklet_hi_schedule(&pr->rRxTask[(num++)%NR_CPUS]);
// tasklet_hi_schedule(&pr->rRxTask);
DBGLOG(HAL, ERROR,](https://linuxcpp.0voice.com/zb_users/upload/2023/05/202305162226144313964.png)
