在检查问题之前，需要注意一些错误和改进：
在主函数中创建链表的方式不正确。应该使用
ListNode* head = new ListNode(1);来创建链表，并逐个链接节点。调用
s.removeNthFromEnd(head, target);删除倒数第n个节点后，需要更新头指针head指向新的链表头。打印链表时应该遍历链表，而不是直接输出头指针的值。
根据以上修正，下面是修改后的代码：
#include <iostream>
struct ListNode {
int val;
ListNode *next;
ListNode() : val(0), next(nullptr) {}
ListNode(int x) : val(x), next(nullptr) {}
ListNode(int x, ListNode *next) : val(x), next(next) {}
};
class Solution {
public:
ListNode* removeNthFromEnd(ListNode* head, int n) {
ListNode* dummy = new ListNode(0, head);
ListNode* pre = dummy;
for (int i = 0; i < n; i++) {
pre = pre->next;
}
while (pre->next) {
pre = pre->next;
head = head->next;
}
head = head->next;
ListNode* ans = dummy->next;
delete dummy;
return ans;
}
};
int main(){
Solution s;
// 创建链表
ListNode* head = new ListNode(1);
head->next = new ListNode(2);
head->next->next = new ListNode(3);
head->next->next->next= new ListNode(4);
head->next->next->next->next = new ListNode(5);
int target = 1;
head = s.removeNthFromEnd(head, target);
// 打印链表
ListNode* curr = head;
while (curr) {
std::cout << curr->val << " ";
curr = curr->next;
}
std::cout << std::endl;
// 释放内存
while (head) {
ListNode* temp = head;
head = head->next;
delete temp;
}
return 0;
}
经过上述修正后，代码应该可以正确运行，并输出删除倒数第n个节点后的链表。
内容由零声教学AI助手提供，问题来源于学员提问
![/data # iw --debug dev wlan0 connect -w "lucky-5g" auth open key 0:1234567890
Usage: iw [options] dev connect [-w] [] [] [auth open|shared] [key 0:abcde d:1:6162636465] [mfp:req/opt/no]
Join the network with ...](https://linuxcpp.0voice.com/zb_users/upload/2023/05/202305162239148267954.png)
![驱动代码
void kalRxTaskletSchedule(struct GLUE_INFO *pr)
{
static unsigned int num = 0;
tasklet_hi_schedule(&pr->rRxTask[(num++)%NR_CPUS]);
// tasklet_hi_schedule(&pr->rRxTask);
DBGLOG(HAL, ERROR,](https://linuxcpp.0voice.com/zb_users/upload/2023/05/202305162226144313964.png)
